Discussion:
Help on a Simple Limit ?
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Randy Yates
2008-05-01 16:51:23 UTC
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I'm trying to find

\lim_{x\rightarrow 0} \frac{2^x - 1}{x}

I know the answer (ln(2)). This is not homework. I'm simply wanting to
determine the way to solve such a limit.

I've applied L'Hopital without success. I've alse tried taking the limit
of \exp{\frac{2^x - 1}{x}}, without success.

I'd appreciate if someone could give me a hint without divulging the
entire solution to give me a chance to solve it on my own first.
--
% Randy Yates % "Rollin' and riding and slippin' and
%% Fuquay-Varina, NC % sliding, it's magic."
%%% 919-577-9882 %
%%%% <***@ieee.org> % 'Living' Thing', *A New World Record*, ELO
http://www.digitalsignallabs.com
Randy Yates
2008-05-01 16:59:08 UTC
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Never mind! I got it! I kept on making the mistake (after applying
L'Hopital) that d(2^x) / dx = x*2^{x-1}, which of course is WRONG!

Thanks for, well, allowing me to ask the question!
--
% Randy Yates % "The dreamer, the unwoken fool -
%% Fuquay-Varina, NC % in dreams, no pain will kiss the brow..."
%%% 919-577-9882 %
%%%% <***@ieee.org> % 'Eldorado Overture', *Eldorado*, ELO
http://www.digitalsignallabs.com
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