Discussion:
Can 4 equal 3?
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P Webster
2007-05-17 00:31:55 UTC
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assume the following:
a + b = c
Then...
4a - 3a = a
4b - 3b = b
4c - 3c = c
and so follows...
4a - 3a + 4b - 3b = 4c - 3c
4a + 4b - 4c = 3a + 3b - 3c
4(a + b + c) = 3(a + b + c)
Therefore:
4 = 3

Please tell me what is wrong.

Paul
bill robertson
2007-05-19 03:22:17 UTC
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Post by P Webster
a + b = c
Then...
4a - 3a = a
4b - 3b = b
4c - 3c = c
and so follows...
4a - 3a + 4b - 3b = 4c - 3c
4a + 4b - 4c = 3a + 3b - 3c
---- This line below is incorrect ----
Post by P Webster
4(a + b + c) = 3(a + b + c)
It should be 4(a+b-c) = 3(a+b-c) but since a+b = c then
4(a+b-c) = 3( a+b-c)
4(c-c) = 3(c-c)
4*0 = 3*0
0 = 0 and not 4=3
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Post by P Webster
4 = 3
Please tell me what is wrong.
Paul
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